| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
How many 6-passenger vans will it take to drive all 75 members of the football team to an away game?
| 9 vans | |
| 13 vans | |
| 4 vans | |
| 3 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{75}{6} \) = 12\(\frac{1}{2}\)
So, it will take 12 full vans and one partially full van to transport the entire team making a total of 13 vans.
If \(\left|a\right| = 7\), which of the following best describes a?
none of these is correct |
|
a = -7 |
|
a = 7 or a = -7 |
|
a = 7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
What is 8a2 x 5a4?
| 40a6 | |
| 13a2 | |
| 40a8 | |
| 40a-2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
8a2 x 5a4
(8 x 5)a(2 + 4)
40a6
If \( \left|b + 5\right| \) + 1 = 7, which of these is a possible value for b?
| -1 | |
| -11 | |
| -25 | |
| -16 |
First, solve for \( \left|b + 5\right| \):
\( \left|b + 5\right| \) + 1 = 7
\( \left|b + 5\right| \) = 7 - 1
\( \left|b + 5\right| \) = 6
The value inside the absolute value brackets can be either positive or negative so (b + 5) must equal + 6 or -6 for \( \left|b + 5\right| \) to equal 6:
| b + 5 = 6 b = 6 - 5 b = 1 | b + 5 = -6 b = -6 - 5 b = -11 |
So, b = -11 or b = 1.
A tiger in a zoo has consumed 60 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 90 pounds?
| 1 | |
| 5 | |
| 7 | |
| 3 |
If the tiger has consumed 60 pounds of food in 6 days that's \( \frac{60}{6} \) = 10 pounds of food per day. The tiger needs to consume 90 - 60 = 30 more pounds of food to reach 90 pounds total. At 10 pounds of food per day that's \( \frac{30}{10} \) = 3 more days.