| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.57 |
| Score | 0% | 71% |
Convert c-4 to remove the negative exponent.
| \( \frac{4}{c} \) | |
| \( \frac{-4}{c} \) | |
| \( \frac{1}{c^4} \) | |
| \( \frac{-1}{-4c} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
If \(\left|a\right| = 7\), which of the following best describes a?
a = -7 |
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none of these is correct |
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a = 7 or a = -7 |
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a = 7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Simplify \( \frac{28}{52} \).
| \( \frac{7}{13} \) | |
| \( \frac{8}{13} \) | |
| \( \frac{5}{18} \) | |
| \( \frac{10}{11} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{52} \) = \( \frac{\frac{28}{4}}{\frac{52}{4}} \) = \( \frac{7}{13} \)
What is \( \sqrt{\frac{4}{64}} \)?
| \(\frac{2}{5}\) | |
| \(\frac{1}{4}\) | |
| 3 | |
| 2\(\frac{1}{4}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{4}{64}} \)
\( \frac{\sqrt{4}}{\sqrt{64}} \)
\( \frac{\sqrt{2^2}}{\sqrt{8^2}} \)
\(\frac{1}{4}\)
14 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?
| 4 | |
| 1 | |
| 6 | |
| 5 |
There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 14 people needing transportation leaving 14 - 9 = 5 who will have to find other transportation.