ASVAB Arithmetic Reasoning Practice Test 70855 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

If a mayor is elected with 52% of the votes cast and 51% of a town's 10,000 voters cast a vote, how many votes did the mayor receive?

50% Answer Correctly
4,386
2,652
2,703
3,111

Solution

If 51% of the town's 10,000 voters cast ballots the number of votes cast is:

(\( \frac{51}{100} \)) x 10,000 = \( \frac{510,000}{100} \) = 5,100

The mayor got 52% of the votes cast which is:

(\( \frac{52}{100} \)) x 5,100 = \( \frac{265,200}{100} \) = 2,652 votes.


2

4! = ?

85% Answer Correctly

4 x 3 x 2 x 1

4 x 3

3 x 2 x 1

5 x 4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


3

What is \( 5 \)\( \sqrt{27} \) - \( 8 \)\( \sqrt{3} \)

38% Answer Correctly
7\( \sqrt{3} \)
-3\( \sqrt{81} \)
40\( \sqrt{9} \)
40\( \sqrt{27} \)

Solution

To subtract these radicals together their radicands must be the same:

5\( \sqrt{27} \) - 8\( \sqrt{3} \)
5\( \sqrt{9 \times 3} \) - 8\( \sqrt{3} \)
5\( \sqrt{3^2 \times 3} \) - 8\( \sqrt{3} \)
(5)(3)\( \sqrt{3} \) - 8\( \sqrt{3} \)
15\( \sqrt{3} \) - 8\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

15\( \sqrt{3} \) - 8\( \sqrt{3} \)
(15 - 8)\( \sqrt{3} \)
7\( \sqrt{3} \)


4

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Bob buys two shirts, each with a regular price of $15, how much money will he save?

70% Answer Correctly
$0.75
$6.75
$4.50
$3.00

Solution

By buying two shirts, Bob will save $15 x \( \frac{30}{100} \) = \( \frac{$15 x 30}{100} \) = \( \frac{$450}{100} \) = $4.50 on the second shirt.


5

A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
37\(\frac{1}{2}\)%
22\(\frac{1}{2}\)%
30%
20%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%