ASVAB Arithmetic Reasoning Practice Test 709450 Results

Your Results Global Average
Questions 5 5
Correct 0 3.71
Score 0% 74%

Review

1

What is (c4)2?

80% Answer Correctly
4c2
2c4
c-2
c8

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(c4)2
c(4 * 2)
c8


2

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

fraction

improper fraction

integer

mixed number


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


3

What is \( \frac{8}{6} \) - \( \frac{7}{14} \)?

61% Answer Correctly
\(\frac{5}{6}\)
1 \( \frac{9}{42} \)
2 \( \frac{8}{42} \)
1 \( \frac{4}{8} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 14 are [14, 28, 42, 56, 70, 84, 98]. The first few multiples they share are [42, 84] making 42 the smallest multiple 6 and 14 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 7}{6 x 7} \) - \( \frac{7 x 3}{14 x 3} \)

\( \frac{56}{42} \) - \( \frac{21}{42} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{56 - 21}{42} \) = \( \frac{35}{42} \) = \(\frac{5}{6}\)


4

What is the least common multiple of 9 and 15?

72% Answer Correctly
45
116
4
71

Solution

The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 have in common.


5

How many 12-passenger vans will it take to drive all 50 members of the football team to an away game?

81% Answer Correctly
6 vans
15 vans
5 vans
14 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{50}{12} \) = 4\(\frac{1}{6}\)

So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.