| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
What is the next number in this sequence: 1, 2, 3, 4, 5, __________ ?
| 6 | |
| -2 | |
| 11 | |
| -3 |
The equation for this sequence is:
an = an-1 + 1
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 1
a6 = 5 + 1
a6 = 6
Alex loaned Latoya $500 at an annual interest rate of 7%. If no payments are made, what is the total amount owed at the end of the first year?
| $515 | |
| $535 | |
| $510 | |
| $505 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $500
i = 0.07 x $500
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $500 + $35Which of the following statements about exponents is false?
all of these are false |
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b1 = 1 |
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b1 = b |
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b0 = 1 |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
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commutative property for division |
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distributive property for multiplication |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
What is \( \frac{8z^6}{3z^2} \)?
| 2\(\frac{2}{3}\)z12 | |
| 2\(\frac{2}{3}\)z4 | |
| 2\(\frac{2}{3}\)z\(\frac{1}{3}\) | |
| 2\(\frac{2}{3}\)z3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{8z^6}{3z^2} \)
\( \frac{8}{3} \) z(6 - 2)
2\(\frac{2}{3}\)z4