| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.49 |
| Score | 0% | 70% |
If \(\left|a\right| = 7\), which of the following best describes a?
a = 7 or a = -7 |
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none of these is correct |
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a = 7 |
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a = -7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Solve for \( \frac{3!}{5!} \)
| 9 | |
| \( \frac{1}{210} \) | |
| \( \frac{1}{840} \) | |
| \( \frac{1}{20} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)
A factor is a positive __________ that divides evenly into a given number.
fraction |
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integer |
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improper fraction |
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mixed number |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
In a class of 32 students, 8 are taking German and 11 are taking Spanish. Of the students studying German or Spanish, 2 are taking both courses. How many students are not enrolled in either course?
| 15 | |
| 28 | |
| 31 | |
| 10 |
The number of students taking German or Spanish is 8 + 11 = 19. Of that group of 19, 2 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 19 - 2 = 17 who are taking at least one language. 32 - 17 = 15 students who are not taking either language.
Ezra loaned Damon $600 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $16 | |
| $28 | |
| $9 | |
| $54 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $600
i = 0.09 x $600
i = $54