| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.46 |
| Score | 0% | 69% |
A factor is a positive __________ that divides evenly into a given number.
mixed number |
|
improper fraction |
|
integer |
|
fraction |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
A tiger in a zoo has consumed 48 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 104 pounds?
| 7 | |
| 8 | |
| 12 | |
| 6 |
If the tiger has consumed 48 pounds of food in 6 days that's \( \frac{48}{6} \) = 8 pounds of food per day. The tiger needs to consume 104 - 48 = 56 more pounds of food to reach 104 pounds total. At 8 pounds of food per day that's \( \frac{56}{8} \) = 7 more days.
Which of the following is a mixed number?
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\({5 \over 7} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is the distance in miles of a trip that takes 5 hours at an average speed of 40 miles per hour?
| 200 miles | |
| 390 miles | |
| 90 miles | |
| 330 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 5h \)
200 miles
What is \( 4 \)\( \sqrt{12} \) - \( 7 \)\( \sqrt{3} \)
| 28\( \sqrt{4} \) | |
| 28\( \sqrt{3} \) | |
| -3\( \sqrt{12} \) | |
| \( \sqrt{3} \) |
To subtract these radicals together their radicands must be the same:
4\( \sqrt{12} \) - 7\( \sqrt{3} \)
4\( \sqrt{4 \times 3} \) - 7\( \sqrt{3} \)
4\( \sqrt{2^2 \times 3} \) - 7\( \sqrt{3} \)
(4)(2)\( \sqrt{3} \) - 7\( \sqrt{3} \)
8\( \sqrt{3} \) - 7\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
8\( \sqrt{3} \) - 7\( \sqrt{3} \)