ASVAB Arithmetic Reasoning Practice Test 715119 Results

Your Results Global Average
Questions 5 5
Correct 0 3.46
Score 0% 69%

Review

1

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

mixed number

improper fraction

integer

fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


2

A tiger in a zoo has consumed 48 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 104 pounds?

56% Answer Correctly
7
8
12
6

Solution

If the tiger has consumed 48 pounds of food in 6 days that's \( \frac{48}{6} \) = 8 pounds of food per day. The tiger needs to consume 104 - 48 = 56 more pounds of food to reach 104 pounds total. At 8 pounds of food per day that's \( \frac{56}{8} \) = 7 more days.


3

Which of the following is a mixed number?

82% Answer Correctly

\({7 \over 5} \)

\({a \over 5} \)

\({5 \over 7} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

What is the distance in miles of a trip that takes 5 hours at an average speed of 40 miles per hour?

87% Answer Correctly
200 miles
390 miles
90 miles
330 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 5h \)
200 miles


5

What is \( 4 \)\( \sqrt{12} \) - \( 7 \)\( \sqrt{3} \)

38% Answer Correctly
28\( \sqrt{4} \)
28\( \sqrt{3} \)
-3\( \sqrt{12} \)
\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{12} \) - 7\( \sqrt{3} \)
4\( \sqrt{4 \times 3} \) - 7\( \sqrt{3} \)
4\( \sqrt{2^2 \times 3} \) - 7\( \sqrt{3} \)
(4)(2)\( \sqrt{3} \) - 7\( \sqrt{3} \)
8\( \sqrt{3} \) - 7\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

8\( \sqrt{3} \) - 7\( \sqrt{3} \)
(8 - 7)\( \sqrt{3} \)
\( \sqrt{3} \)