ASVAB Arithmetic Reasoning Practice Test 715173 Results

Your Results Global Average
Questions 5 5
Correct 0 3.63
Score 0% 73%

Review

1

What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?

92% Answer Correctly
38
36
29
32

Solution

The equation for this sequence is:

an = an-1 + 7

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 7
a6 = 29 + 7
a6 = 36


2

Simplify \( \frac{40}{76} \).

77% Answer Correctly
\( \frac{3}{5} \)
\( \frac{1}{2} \)
\( \frac{2}{7} \)
\( \frac{10}{19} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{40}{76} \) = \( \frac{\frac{40}{4}}{\frac{76}{4}} \) = \( \frac{10}{19} \)


3

If the ratio of home fans to visiting fans in a crowd is 4:1 and all 32,000 seats in a stadium are filled, how many home fans are in attendance?

49% Answer Correctly
41,667
25,600
33,333
27,500

Solution

A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:

32,000 fans x \( \frac{4}{5} \) = \( \frac{128000}{5} \) = 25,600 fans.


4

Bob loaned Christine $700 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$763
$742
$735
$707

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $700
i = 0.06 x $700

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $700 + $42
total = $742


5

What is \( \frac{27\sqrt{40}}{9\sqrt{8}} \)?

71% Answer Correctly
3 \( \sqrt{5} \)
\(\frac{1}{3}\) \( \sqrt{\frac{1}{5}} \)
5 \( \sqrt{\frac{1}{3}} \)
\(\frac{1}{3}\) \( \sqrt{5} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{27\sqrt{40}}{9\sqrt{8}} \)
\( \frac{27}{9} \) \( \sqrt{\frac{40}{8}} \)
3 \( \sqrt{5} \)