ASVAB Arithmetic Reasoning Practice Test 715320 Results

Your Results Global Average
Questions 5 5
Correct 0 3.51
Score 0% 70%

Review

1

What is the least common multiple of 2 and 4?

73% Answer Correctly
5
6
4
2

Solution

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 have in common.


2

Simplify \( \sqrt{32} \)

62% Answer Correctly
2\( \sqrt{2} \)
4\( \sqrt{4} \)
8\( \sqrt{4} \)
4\( \sqrt{2} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{32} \)
\( \sqrt{16 \times 2} \)
\( \sqrt{4^2 \times 2} \)
4\( \sqrt{2} \)


3

If a car travels 65 miles in 1 hour, what is the average speed?

86% Answer Correctly
75 mph
35 mph
25 mph
65 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)
speed = \( \frac{65mi}{1h} \)
65 mph


4

If \( \left|x + 8\right| \) + 5 = 2, which of these is a possible value for x?

62% Answer Correctly
-5
-14
14
6

Solution

First, solve for \( \left|x + 8\right| \):

\( \left|x + 8\right| \) + 5 = 2
\( \left|x + 8\right| \) = 2 - 5
\( \left|x + 8\right| \) = -3

The value inside the absolute value brackets can be either positive or negative so (x + 8) must equal - 3 or --3 for \( \left|x + 8\right| \) to equal -3:

x + 8 = -3
x = -3 - 8
x = -11
x + 8 = 3
x = 3 - 8
x = -5

So, x = -5 or x = -11.


5

What is \( \frac{2}{8} \) ÷ \( \frac{3}{6} \)?

68% Answer Correctly
\(\frac{1}{8}\)
\(\frac{1}{2}\)
1\(\frac{1}{2}\)
\(\frac{1}{48}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{8} \) ÷ \( \frac{3}{6} \) = \( \frac{2}{8} \) x \( \frac{6}{3} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{8} \) x \( \frac{6}{3} \) = \( \frac{2 x 6}{8 x 3} \) = \( \frac{12}{24} \) = \(\frac{1}{2}\)