| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
Solve 4 + (4 + 2) ÷ 2 x 4 - 32
| 1\(\frac{1}{2}\) | |
| \(\frac{5}{9}\) | |
| 7 | |
| 3 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (4 + 2) ÷ 2 x 4 - 32
P: 4 + (6) ÷ 2 x 4 - 32
E: 4 + 6 ÷ 2 x 4 - 9
MD: 4 + \( \frac{6}{2} \) x 4 - 9
MD: 4 + \( \frac{24}{2} \) - 9
AS: \( \frac{8}{2} \) + \( \frac{24}{2} \) - 9
AS: \( \frac{32}{2} \) - 9
AS: \( \frac{32 - 18}{2} \)
\( \frac{14}{2} \)
7
What is \( 5 \)\( \sqrt{32} \) + \( 2 \)\( \sqrt{2} \)
| 10\( \sqrt{16} \) | |
| 10\( \sqrt{32} \) | |
| 7\( \sqrt{32} \) | |
| 22\( \sqrt{2} \) |
To add these radicals together their radicands must be the same:
5\( \sqrt{32} \) + 2\( \sqrt{2} \)
5\( \sqrt{16 \times 2} \) + 2\( \sqrt{2} \)
5\( \sqrt{4^2 \times 2} \) + 2\( \sqrt{2} \)
(5)(4)\( \sqrt{2} \) + 2\( \sqrt{2} \)
20\( \sqrt{2} \) + 2\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
20\( \sqrt{2} \) + 2\( \sqrt{2} \)A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 9 to 2 and the ratio of baseball to basketball cards is 9 to 1, what is the ratio of football to basketball cards?
| 9:8 | |
| 5:4 | |
| 1:1 | |
| 81:2 |
The ratio of football cards to baseball cards is 9:2 and the ratio of baseball cards to basketball cards is 9:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 81:18 and the ratio of baseball cards to basketball cards as 18:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 81:18, 18:2 which reduces to 81:2.
What is the least common multiple of 2 and 8?
| 8 | |
| 7 | |
| 10 | |
| 2 |
The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 2 and 8 have in common.
A tiger in a zoo has consumed 65 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 130 pounds?
| 5 | |
| 1 | |
| 10 | |
| 6 |
If the tiger has consumed 65 pounds of food in 5 days that's \( \frac{65}{5} \) = 13 pounds of food per day. The tiger needs to consume 130 - 65 = 65 more pounds of food to reach 130 pounds total. At 13 pounds of food per day that's \( \frac{65}{13} \) = 5 more days.