ASVAB Arithmetic Reasoning Practice Test 718298 Results

Your Results Global Average
Questions 5 5
Correct 0 3.08
Score 0% 62%

Review

1

What is the greatest common factor of 20 and 64?

77% Answer Correctly
13
4
3
9

Solution

The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 3 factors [1, 2, 4] making 4 the greatest factor 20 and 64 have in common.


2

A machine in a factory has an error rate of 9 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
149.9
146.3
100.1
133.8

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{9}{100} \) x 5 = \( \frac{9 \times 5}{100} \) = \( \frac{45}{100} \) = 0.45 errors per hour

So, in an average hour, the machine will produce 5 - 0.45 = 4.55 error free parts.

The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 4.55 = 100.1 error free parts were produced yesterday.


3

The total water usage for a city is 10,000 gallons each day. Of that total, 21% is for personal use and 38% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
4,400
2,600
6,000
1,700

Solution

38% of the water consumption is industrial use and 21% is personal use so (38% - 21%) = 17% more water is used for industrial purposes. 10,000 gallons are consumed daily so industry consumes \( \frac{17}{100} \) x 10,000 gallons = 1,700 gallons.


4

What is \( \frac{5y^5}{6y^4} \)?

60% Answer Correctly
1\(\frac{1}{5}\)y
\(\frac{5}{6}\)y
\(\frac{5}{6}\)y-1
\(\frac{5}{6}\)y9

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{5y^5}{6y^4} \)
\( \frac{5}{6} \) y(5 - 4)
\(\frac{5}{6}\)y


5

If \( \left|x + 5\right| \) + 3 = 4, which of these is a possible value for x?

62% Answer Correctly
-9
-7
-6
-1

Solution

First, solve for \( \left|x + 5\right| \):

\( \left|x + 5\right| \) + 3 = 4
\( \left|x + 5\right| \) = 4 - 3
\( \left|x + 5\right| \) = 1

The value inside the absolute value brackets can be either positive or negative so (x + 5) must equal + 1 or -1 for \( \left|x + 5\right| \) to equal 1:

x + 5 = 1
x = 1 - 5
x = -4
x + 5 = -1
x = -1 - 5
x = -6

So, x = -6 or x = -4.