| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
In a class of 22 students, 9 are taking German and 9 are taking Spanish. Of the students studying German or Spanish, 6 are taking both courses. How many students are not enrolled in either course?
| 16 | |
| 19 | |
| 14 | |
| 10 |
The number of students taking German or Spanish is 9 + 9 = 18. Of that group of 18, 6 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 18 - 6 = 12 who are taking at least one language. 22 - 12 = 10 students who are not taking either language.
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?
| 7 | |
| 4 | |
| 6 | |
| 2 |
To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2
The __________ is the greatest factor that divides two integers.
least common multiple |
|
greatest common factor |
|
greatest common multiple |
|
absolute value |
The greatest common factor (GCF) is the greatest factor that divides two integers.
Solve for \( \frac{2!}{4!} \)
| \( \frac{1}{12} \) | |
| \( \frac{1}{8} \) | |
| \( \frac{1}{60480} \) | |
| 56 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{4!} \)
\( \frac{2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4 \times 3} \)
\( \frac{1}{12} \)
What is \( \frac{8}{3} \) + \( \frac{2}{9} \)?
| \( \frac{1}{9} \) | |
| 2 \( \frac{4}{7} \) | |
| 1 \( \frac{8}{9} \) | |
| 2\(\frac{8}{9}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 3}{3 x 3} \) + \( \frac{2 x 1}{9 x 1} \)
\( \frac{24}{9} \) + \( \frac{2}{9} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{24 + 2}{9} \) = \( \frac{26}{9} \) = 2\(\frac{8}{9}\)