If a single cook can bake 5 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 5 x 2 = 10 large cakes during that time. 23 large cakes are needed for the party so \( \frac{23}{10} \) = 2\(\frac{3}{10}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 19 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 19 x 2 = 38 small cakes during that time. 280 small cakes are needed for the party so \( \frac{280}{38} \) = 7\(\frac{7}{19}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 8 = 11 cooks.

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

2z³ - 6z³
(2 - 6)z³
-4z³

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-4z⁵ + 8z⁵
(-4 + 8)z⁵
4z⁵

By buying two shirts, Monty will save $49 x \( \frac{40}{100} \) = \( \frac{$49 x 40}{100} \) = \( \frac{$1960}{100} \) = $19.60 on the second shirt.

So, his total cost will be
$49.00 + ($49.00 - $19.60)
$49.00 + $29.40
$78.40

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 2 and 8 have in common.