ASVAB Arithmetic Reasoning Practice Test 720778 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

What is \( 2 \)\( \sqrt{48} \) - \( 8 \)\( \sqrt{3} \)

38% Answer Correctly
-6\( \sqrt{16} \)
16\( \sqrt{144} \)
-6\( \sqrt{144} \)
0\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

2\( \sqrt{48} \) - 8\( \sqrt{3} \)
2\( \sqrt{16 \times 3} \) - 8\( \sqrt{3} \)
2\( \sqrt{4^2 \times 3} \) - 8\( \sqrt{3} \)
(2)(4)\( \sqrt{3} \) - 8\( \sqrt{3} \)
8\( \sqrt{3} \) - 8\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

8\( \sqrt{3} \) - 8\( \sqrt{3} \)
(8 - 8)\( \sqrt{3} \)
0\( \sqrt{3} \)


2

What is the greatest common factor of 32 and 52?

77% Answer Correctly
4
18
22
16

Solution

The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 the greatest factor 32 and 52 have in common.


3

What is \( \frac{2c^5}{6c^3} \)?

60% Answer Correctly
\(\frac{1}{3}\)c-2
3c8
\(\frac{1}{3}\)c8
\(\frac{1}{3}\)c2

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{2c^5}{6c^3} \)
\( \frac{2}{6} \) c(5 - 3)
\(\frac{1}{3}\)c2


4

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Charlie buys two shirts, each with a regular price of $34, how much money will he save?

70% Answer Correctly
$10.20
$1.70
$17.00
$8.50

Solution

By buying two shirts, Charlie will save $34 x \( \frac{5}{100} \) = \( \frac{$34 x 5}{100} \) = \( \frac{$170}{100} \) = $1.70 on the second shirt.


5

What is \( \frac{4}{7} \) ÷ \( \frac{3}{9} \)?

68% Answer Correctly
1\(\frac{5}{7}\)
\(\frac{6}{35}\)
12
\(\frac{4}{21}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{7} \) ÷ \( \frac{3}{9} \) = \( \frac{4}{7} \) x \( \frac{9}{3} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{7} \) x \( \frac{9}{3} \) = \( \frac{4 x 9}{7 x 3} \) = \( \frac{36}{21} \) = 1\(\frac{5}{7}\)