ASVAB Arithmetic Reasoning Practice Test 725394 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

mixed number

improper fraction

fraction

integer


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


2

What is \( \frac{6\sqrt{6}}{2\sqrt{2}} \)?

71% Answer Correctly
3 \( \sqrt{3} \)
\(\frac{1}{3}\) \( \sqrt{\frac{1}{3}} \)
\(\frac{1}{3}\) \( \sqrt{3} \)
3 \( \sqrt{\frac{1}{3}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{6\sqrt{6}}{2\sqrt{2}} \)
\( \frac{6}{2} \) \( \sqrt{\frac{6}{2}} \)
3 \( \sqrt{3} \)


3

If \( \left|b + 0\right| \) - 9 = 7, which of these is a possible value for b?

62% Answer Correctly
-16
-5
9
-6

Solution

First, solve for \( \left|b + 0\right| \):

\( \left|b + 0\right| \) - 9 = 7
\( \left|b + 0\right| \) = 7 + 9
\( \left|b + 0\right| \) = 16

The value inside the absolute value brackets can be either positive or negative so (b + 0) must equal + 16 or -16 for \( \left|b + 0\right| \) to equal 16:

b + 0 = 16
b = 16 + 0
b = 16
b + 0 = -16
b = -16 + 0
b = -16

So, b = -16 or b = 16.


4

What is -5c3 x 6c5?

75% Answer Correctly
-30c8
-30c-2
c3
-30c2

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-5c3 x 6c5
(-5 x 6)c(3 + 5)
-30c8


5

A tiger in a zoo has consumed 42 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 63 pounds?

56% Answer Correctly
3
9
6
4

Solution

If the tiger has consumed 42 pounds of food in 6 days that's \( \frac{42}{6} \) = 7 pounds of food per day. The tiger needs to consume 63 - 42 = 21 more pounds of food to reach 63 pounds total. At 7 pounds of food per day that's \( \frac{21}{7} \) = 3 more days.