| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
A triathlon course includes a 300m swim, a 40.6km bike ride, and a 16.8km run. What is the total length of the race course?
| 48km | |
| 33.5km | |
| 32.4km | |
| 57.7km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.3km + 40.6km + 16.8km
total distance = 57.7km
What is \( 9 \)\( \sqrt{28} \) + \( 9 \)\( \sqrt{7} \)
| 27\( \sqrt{7} \) | |
| 18\( \sqrt{7} \) | |
| 18\( \sqrt{196} \) | |
| 18\( \sqrt{28} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{28} \) + 9\( \sqrt{7} \)
9\( \sqrt{4 \times 7} \) + 9\( \sqrt{7} \)
9\( \sqrt{2^2 \times 7} \) + 9\( \sqrt{7} \)
(9)(2)\( \sqrt{7} \) + 9\( \sqrt{7} \)
18\( \sqrt{7} \) + 9\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
18\( \sqrt{7} \) + 9\( \sqrt{7} \)What is \( \frac{3}{8} \) - \( \frac{7}{16} \)?
| -\(\frac{1}{16}\) | |
| \( \frac{2}{16} \) | |
| 1 \( \frac{2}{11} \) | |
| 1 \( \frac{8}{17} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 16 are [16, 32, 48, 64, 80, 96]. The first few multiples they share are [16, 32, 48, 64, 80] making 16 the smallest multiple 8 and 16 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 2}{8 x 2} \) - \( \frac{7 x 1}{16 x 1} \)
\( \frac{6}{16} \) - \( \frac{7}{16} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{6 - 7}{16} \) = \( \frac{-1}{16} \) = -\(\frac{1}{16}\)
A bread recipe calls for 3\(\frac{5}{8}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?
| 1\(\frac{1}{4}\) cups | |
| 2\(\frac{3}{8}\) cups | |
| 1\(\frac{7}{8}\) cups | |
| 2 cups |
The amount of flour you need is (3\(\frac{5}{8}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{29}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{19}{8} \) cups
2\(\frac{3}{8}\) cups
What is \( \sqrt{\frac{25}{49}} \)?
| \(\frac{1}{4}\) | |
| 1 | |
| \(\frac{5}{7}\) | |
| \(\frac{2}{7}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{25}{49}} \)
\( \frac{\sqrt{25}}{\sqrt{49}} \)
\( \frac{\sqrt{5^2}}{\sqrt{7^2}} \)
\(\frac{5}{7}\)