| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.41 |
| Score | 0% | 68% |
Which of the following is not an integer?
-1 |
|
0 |
|
1 |
|
\({1 \over 2}\) |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
Find the average of the following numbers: 9, 3, 8, 4.
| 6 | |
| 8 | |
| 2 | |
| 7 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{9 + 3 + 8 + 4}{4} \) = \( \frac{24}{4} \) = 6
What is 4y2 x 9y2?
| 13y4 | |
| 13y2 | |
| 36y4 | |
| 36y2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
4y2 x 9y2
(4 x 9)y(2 + 2)
36y4
| 1 | |
| 1.0 | |
| 2.7 | |
| 0.4 |
1
What is \( \frac{-6z^5}{1z^3} \)?
| -6z8 | |
| -\(\frac{1}{6}\)z-2 | |
| -\(\frac{1}{6}\)z2 | |
| -6z2 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-6z^5}{z^3} \)
\( \frac{-6}{1} \) z(5 - 3)
-6z2