| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.78 |
| Score | 0% | 56% |
A bread recipe calls for 2\(\frac{1}{8}\) cups of flour. If you only have 1\(\frac{5}{8}\) cups, how much more flour is needed?
| \(\frac{1}{2}\) cups | |
| 1\(\frac{7}{8}\) cups | |
| 1\(\frac{1}{8}\) cups | |
| 1\(\frac{3}{4}\) cups |
The amount of flour you need is (2\(\frac{1}{8}\) - 1\(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{17}{8} \) - \( \frac{13}{8} \)) cups
\( \frac{4}{8} \) cups
\(\frac{1}{2}\) cups
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Frank buys two shirts, each with a regular price of $19, how much will he pay for both shirts?
| $34.20 | |
| $22.80 | |
| $3.80 | |
| $25.65 |
By buying two shirts, Frank will save $19 x \( \frac{20}{100} \) = \( \frac{$19 x 20}{100} \) = \( \frac{$380}{100} \) = $3.80 on the second shirt.
So, his total cost will be
$19.00 + ($19.00 - $3.80)
$19.00 + $15.20
$34.20
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 49,000 seats in a stadium are filled, how many home fans are in attendance?
| 27,333 | |
| 26,400 | |
| 36,800 | |
| 40,833 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
49,000 fans x \( \frac{5}{6} \) = \( \frac{245000}{6} \) = 40,833 fans.
If \(\left|a\right| = 7\), which of the following best describes a?
none of these is correct |
|
a = -7 |
|
a = 7 |
|
a = 7 or a = -7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 12 small cakes per hour. The kitchen is available for 4 hours and 39 large cakes and 110 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 14 | |
| 5 | |
| 8 | |
| 7 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 39 large cakes are needed for the party so \( \frac{39}{8} \) = 4\(\frac{7}{8}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 12 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 12 x 4 = 48 small cakes during that time. 110 small cakes are needed for the party so \( \frac{110}{48} \) = 2\(\frac{7}{24}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 3 = 8 cooks.