To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 6 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 4}{6 x 4} \) - \( \frac{8 x 3}{8 x 3} \)

\( \frac{20}{24} \) - \( \frac{24}{24} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{20 - 24}{24} \) = \( \frac{-4}{24} \) = -\(\frac{1}{6}\)

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (3 + 4) ÷ 5 x 5 - 3²
P: 3 + (7) ÷ 5 x 5 - 3²
E: 3 + 7 ÷ 5 x 5 - 9
MD: 3 + \( \frac{7}{5} \) x 5 - 9
MD: 3 + \( \frac{35}{5} \) - 9
AS: \( \frac{15}{5} \) + \( \frac{35}{5} \) - 9
AS: \( \frac{50}{5} \) - 9
AS: \( \frac{50 - 45}{5} \)
\( \frac{5}{5} \)
1

You have 24 out of the total of 300 raffle tickets sold so you have a (\( \frac{24}{300} \)) x 100 = \( \frac{24 \times 100}{300} \) = \( \frac{2400}{300} \) = 8% chance to win the raffle.

If the tiger has consumed 77 pounds of food in 7 days that's \( \frac{77}{7} \) = 11 pounds of food per day. The tiger needs to consume 154 - 77 = 77 more pounds of food to reach 154 pounds total. At 11 pounds of food per day that's \( \frac{77}{11} \) = 7 more days.

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.