| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.48 |
| Score | 0% | 70% |
4! = ?
4 x 3 |
|
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is 7\( \sqrt{3} \) x 5\( \sqrt{6} \)?
| 105\( \sqrt{2} \) | |
| 12\( \sqrt{3} \) | |
| 35\( \sqrt{9} \) | |
| 12\( \sqrt{18} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
7\( \sqrt{3} \) x 5\( \sqrt{6} \)
(7 x 5)\( \sqrt{3 \times 6} \)
35\( \sqrt{18} \)
Now we need to simplify the radical:
35\( \sqrt{18} \)
35\( \sqrt{2 \times 9} \)
35\( \sqrt{2 \times 3^2} \)
(35)(3)\( \sqrt{2} \)
105\( \sqrt{2} \)
What is (b5)3?
| b-2 | |
| 5b3 | |
| b2 | |
| b15 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b5)3What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 52 | |
| 39 | |
| 46 | |
| 40 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46
Find the average of the following numbers: 11, 9, 13, 7.
| 10 | |
| 13 | |
| 15 | |
| 11 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{11 + 9 + 13 + 7}{4} \) = \( \frac{40}{4} \) = 10