| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
A tiger in a zoo has consumed 120 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 195 pounds?
| 13 | |
| 10 | |
| 4 | |
| 5 |
If the tiger has consumed 120 pounds of food in 8 days that's \( \frac{120}{8} \) = 15 pounds of food per day. The tiger needs to consume 195 - 120 = 75 more pounds of food to reach 195 pounds total. At 15 pounds of food per day that's \( \frac{75}{15} \) = 5 more days.
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 5:6 | |
| 3:1 | |
| 49:2 | |
| 5:1 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
What is \( \sqrt{\frac{49}{36}} \)?
| 1\(\frac{1}{6}\) | |
| \(\frac{7}{9}\) | |
| \(\frac{2}{5}\) | |
| 1\(\frac{1}{4}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{49}{36}} \)
\( \frac{\sqrt{49}}{\sqrt{36}} \)
\( \frac{\sqrt{7^2}}{\sqrt{6^2}} \)
\( \frac{7}{6} \)
1\(\frac{1}{6}\)
If \( \left|y + 2\right| \) + 1 = 2, which of these is a possible value for y?
| -5 | |
| -3 | |
| 15 | |
| -11 |
First, solve for \( \left|y + 2\right| \):
\( \left|y + 2\right| \) + 1 = 2
\( \left|y + 2\right| \) = 2 - 1
\( \left|y + 2\right| \) = 1
The value inside the absolute value brackets can be either positive or negative so (y + 2) must equal + 1 or -1 for \( \left|y + 2\right| \) to equal 1:
| y + 2 = 1 y = 1 - 2 y = -1 | y + 2 = -1 y = -1 - 2 y = -3 |
So, y = -3 or y = -1.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 15% off." If Roger buys two shirts, each with a regular price of $19, how much money will he save?
| $7.60 | |
| $2.85 | |
| $0.95 | |
| $6.65 |
By buying two shirts, Roger will save $19 x \( \frac{15}{100} \) = \( \frac{$19 x 15}{100} \) = \( \frac{$285}{100} \) = $2.85 on the second shirt.