| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.35 |
| Score | 0% | 67% |
What is (x5)5?
| x0 | |
| x25 | |
| 5x5 | |
| x10 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x5)5A triathlon course includes a 100m swim, a 30.9km bike ride, and a 7.800000000000001km run. What is the total length of the race course?
| 38.8km | |
| 44.7km | |
| 28.4km | |
| 56.6km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 30.9km + 7.800000000000001km
total distance = 38.8km
What is the greatest common factor of 80 and 48?
| 35 | |
| 31 | |
| 16 | |
| 37 |
The factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 5 factors [1, 2, 4, 8, 16] making 16 the greatest factor 80 and 48 have in common.
The __________ is the smallest positive integer that is a multiple of two or more integers.
absolute value |
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least common multiple |
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greatest common factor |
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least common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 9 | |
| 7 | |
| 4 | |
| 2 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 6 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 6 x 3 = 18 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 18 - 9 = 9 new staff for the busy season.