| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
The total water usage for a city is 50,000 gallons each day. Of that total, 21% is for personal use and 36% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 8,400 | |
| 7,500 | |
| 2,850 | |
| 1,600 |
36% of the water consumption is industrial use and 21% is personal use so (36% - 21%) = 15% more water is used for industrial purposes. 50,000 gallons are consumed daily so industry consumes \( \frac{15}{100} \) x 50,000 gallons = 7,500 gallons.
4! = ?
3 x 2 x 1 |
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4 x 3 x 2 x 1 |
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5 x 4 x 3 x 2 x 1 |
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4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 30% larger than the original. By what percentage has the area of the logo increased?
| 15% | |
| 25% | |
| 30% | |
| 37\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 30% the radius (and, consequently, the total area) increases by \( \frac{30\text{%}}{2} \) = 15%
a(b + c) = ab + ac defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for division |
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commutative property for multiplication |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
What is \( 3 \)\( \sqrt{8} \) + \( 4 \)\( \sqrt{2} \)
| 7\( \sqrt{2} \) | |
| 7\( \sqrt{16} \) | |
| 10\( \sqrt{2} \) | |
| 12\( \sqrt{16} \) |
To add these radicals together their radicands must be the same:
3\( \sqrt{8} \) + 4\( \sqrt{2} \)
3\( \sqrt{4 \times 2} \) + 4\( \sqrt{2} \)
3\( \sqrt{2^2 \times 2} \) + 4\( \sqrt{2} \)
(3)(2)\( \sqrt{2} \) + 4\( \sqrt{2} \)
6\( \sqrt{2} \) + 4\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
6\( \sqrt{2} \) + 4\( \sqrt{2} \)