If a single cook can bake 5 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 5 x 3 = 15 large cakes during that time. 33 large cakes are needed for the party so \( \frac{33}{15} \) = 2\(\frac{1}{5}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 10 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 10 x 3 = 30 small cakes during that time. 500 small cakes are needed for the party so \( \frac{500}{30} \) = 16\(\frac{2}{3}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 17 = 20 cooks.

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{14 + 10 + 15 + 9}{4} \) = \( \frac{48}{4} \) = 12

If the tiger has consumed 90 pounds of food in 6 days that's \( \frac{90}{6} \) = 15 pounds of food per day. The tiger needs to consume 165 - 90 = 75 more pounds of food to reach 165 pounds total. At 15 pounds of food per day that's \( \frac{75}{15} \) = 5 more days.

The equation for this sequence is:

a_n = a_n-1 + 3(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 3(6 - 1)
a₆ = 31 + 3(5)
a₆ = 46

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,400
i = 0.07 x $1,400

No payments were made so the total amount due is the original amount + the accumulated interest: