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The __________ is the smallest positive integer that is a multiple of two or more integers.
least common multiple |
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absolute value |
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least common factor |
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greatest common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
a(b + c) = ab + ac defines which of the following?
commutative property for division |
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distributive property for division |
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commutative property for multiplication |
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distributive property for multiplication |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
What is \( 4 \)\( \sqrt{50} \) + \( 8 \)\( \sqrt{2} \)
| 12\( \sqrt{50} \) | |
| 12\( \sqrt{100} \) | |
| 28\( \sqrt{2} \) | |
| 12\( \sqrt{2} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{50} \) + 8\( \sqrt{2} \)
4\( \sqrt{25 \times 2} \) + 8\( \sqrt{2} \)
4\( \sqrt{5^2 \times 2} \) + 8\( \sqrt{2} \)
(4)(5)\( \sqrt{2} \) + 8\( \sqrt{2} \)
20\( \sqrt{2} \) + 8\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
20\( \sqrt{2} \) + 8\( \sqrt{2} \)A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
| 2\(\frac{7}{8}\) cups | |
| 2\(\frac{5}{8}\) cups | |
| 1\(\frac{5}{8}\) cups | |
| 2\(\frac{3}{8}\) cups |
The amount of flour you need is (3\(\frac{3}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{27}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{23}{8} \) cups
2\(\frac{7}{8}\) cups
What is \( \sqrt{\frac{25}{4}} \)?
| \(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| 1 | |
| \(\frac{7}{8}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{25}{4}} \)
\( \frac{\sqrt{25}}{\sqrt{4}} \)
\( \frac{\sqrt{5^2}}{\sqrt{2^2}} \)
\( \frac{5}{2} \)
2\(\frac{1}{2}\)