ASVAB Arithmetic Reasoning Practice Test 733146 Results

Your Results Global Average
Questions 5 5
Correct 0 3.12
Score 0% 62%

Review

1

A triathlon course includes a 500m swim, a 30.9km bike ride, and a 15.9km run. What is the total length of the race course?

69% Answer Correctly
51.9km
47.3km
30km
31.5km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.5km + 30.9km + 15.9km
total distance = 47.3km


2

What is \( \frac{4}{3} \) - \( \frac{8}{7} \)?

61% Answer Correctly
2 \( \frac{8}{12} \)
\(\frac{4}{21}\)
\( \frac{2}{21} \)
\( \frac{6}{21} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 7}{3 x 7} \) - \( \frac{8 x 3}{7 x 3} \)

\( \frac{28}{21} \) - \( \frac{24}{21} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{28 - 24}{21} \) = \( \frac{4}{21} \) = \(\frac{4}{21}\)


3

What is (y3)3?

80% Answer Correctly
y6
3y3
y9
y0

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(y3)3
y(3 * 3)
y9


4

What is 9\( \sqrt{9} \) x 5\( \sqrt{9} \)?

41% Answer Correctly
45\( \sqrt{18} \)
135\( \sqrt{9} \)
45\( \sqrt{9} \)
14\( \sqrt{9} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

9\( \sqrt{9} \) x 5\( \sqrt{9} \)
(9 x 5)\( \sqrt{9 \times 9} \)
45\( \sqrt{81} \)

Now we need to simplify the radical:

45\( \sqrt{81} \)
45\( \sqrt{9 \times 9} \)
45\( \sqrt{9 \times 3^2} \)
(45)(3)\( \sqrt{9} \)
135\( \sqrt{9} \)


5

A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have 1\(\frac{5}{8}\) cups, how much more flour is needed?

62% Answer Correctly
1\(\frac{1}{4}\) cups
2\(\frac{1}{2}\) cups
1\(\frac{1}{2}\) cups
1\(\frac{3}{4}\) cups

Solution

The amount of flour you need is (3\(\frac{3}{8}\) - 1\(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{27}{8} \) - \( \frac{13}{8} \)) cups
\( \frac{14}{8} \) cups
1\(\frac{3}{4}\) cups