| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
A tiger in a zoo has consumed 90 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 165 pounds?
| 10 | |
| 7 | |
| 3 | |
| 5 |
If the tiger has consumed 90 pounds of food in 6 days that's \( \frac{90}{6} \) = 15 pounds of food per day. The tiger needs to consume 165 - 90 = 75 more pounds of food to reach 165 pounds total. At 15 pounds of food per day that's \( \frac{75}{15} \) = 5 more days.
What is (x4)5?
| x20 | |
| x | |
| x-1 | |
| 5x4 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x4)5On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 32 | |
| 33 | |
| 42 | |
| 37 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{55}{100} \) = \( \frac{55 x 25}{100} \) = \( \frac{1375}{100} \) = 13 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{13}{\frac{40}{100}} \) = 13 x \( \frac{100}{40} \) = \( \frac{13 x 100}{40} \) = \( \frac{1300}{40} \) = 33 shots
to make the same number of shots as the guard and thus score the same number of points.
How many 14-passenger vans will it take to drive all 98 members of the football team to an away game?
| 13 vans | |
| 6 vans | |
| 7 vans | |
| 15 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{98}{14} \) = 7
What is \( 4 \)\( \sqrt{48} \) + \( 6 \)\( \sqrt{3} \)
| 10\( \sqrt{48} \) | |
| 24\( \sqrt{16} \) | |
| 22\( \sqrt{3} \) | |
| 24\( \sqrt{144} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{48} \) + 6\( \sqrt{3} \)
4\( \sqrt{16 \times 3} \) + 6\( \sqrt{3} \)
4\( \sqrt{4^2 \times 3} \) + 6\( \sqrt{3} \)
(4)(4)\( \sqrt{3} \) + 6\( \sqrt{3} \)
16\( \sqrt{3} \) + 6\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
16\( \sqrt{3} \) + 6\( \sqrt{3} \)