Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (3 + 3) ÷ 5 x 3 - 4²
P: 2 + (6) ÷ 5 x 3 - 4²
E: 2 + 6 ÷ 5 x 3 - 16
MD: 2 + \( \frac{6}{5} \) x 3 - 16
MD: 2 + \( \frac{18}{5} \) - 16
AS: \( \frac{10}{5} \) + \( \frac{18}{5} \) - 16
AS: \( \frac{28}{5} \) - 16
AS: \( \frac{28 - 80}{5} \)
\( \frac{-52}{5} \)
-10\(\frac{2}{5}\)

First, solve for \( \left|x - 5\right| \):

\( \left|x - 5\right| \) - 3 = 6
\( \left|x - 5\right| \) = 6 + 3
\( \left|x - 5\right| \) = 9

The value inside the absolute value brackets can be either positive or negative so (x - 5) must equal + 9 or -9 for \( \left|x - 5\right| \) to equal 9:

So, x = -4 or x = 14.

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.

The equation for this sequence is:

a_n = a_n-1 + 1

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 1
a₆ = 5 + 1
a₆ = 6

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.