ASVAB Arithmetic Reasoning Practice Test 739770 Results

Your Results Global Average
Questions 5 5
Correct 0 3.07
Score 0% 61%

Review

1

4! = ?

84% Answer Correctly

4 x 3

5 x 4 x 3 x 2 x 1

3 x 2 x 1

4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


2

If the ratio of home fans to visiting fans in a crowd is 2:1 and all 39,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
33,333
26,000
27,500
41,667

Solution

A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:

39,000 fans x \( \frac{2}{3} \) = \( \frac{78000}{3} \) = 26,000 fans.


3

What is 8y3 x y2?

75% Answer Correctly
9y2
8y5
9y3
8y3

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

8y3 x y2
(8 x 1)y(3 + 2)
8y5


4

A machine in a factory has an error rate of 5 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
186
78.2
102.9
104.5

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{5}{100} \) x 5 = \( \frac{5 \times 5}{100} \) = \( \frac{25}{100} \) = 0.25 errors per hour

So, in an average hour, the machine will produce 5 - 0.25 = 4.75 error free parts.

The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 4.75 = 104.5 error free parts were produced yesterday.


5

If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?

47% Answer Correctly
50 m2
72 m2
162 m2
18 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.

Putting these two equations together and solving for width (w):

2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5

Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2