| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
What is -8c5 + 6c5?
| -14c5 | |
| 14c-5 | |
| -2c5 | |
| -2c10 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-8c5 + 6c5
(-8 + 6)c5
-2c5
A tiger in a zoo has consumed 30 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 45 pounds?
| 2 | |
| 7 | |
| 3 | |
| 9 |
If the tiger has consumed 30 pounds of food in 6 days that's \( \frac{30}{6} \) = 5 pounds of food per day. The tiger needs to consume 45 - 30 = 15 more pounds of food to reach 45 pounds total. At 5 pounds of food per day that's \( \frac{15}{5} \) = 3 more days.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Ezra buys two shirts, each with a regular price of $34, how much money will he save?
| $10.20 | |
| $13.60 | |
| $8.50 | |
| 42 |
By buying two shirts, Ezra will save $34 x \( \frac{30}{100} \) = \( \frac{$34 x 30}{100} \) = \( \frac{$1020}{100} \) = $10.20 on the second shirt.
Solve 3 + (4 + 2) ÷ 5 x 2 - 42
| -10\(\frac{3}{5}\) | |
| 1\(\frac{2}{5}\) | |
| \(\frac{7}{9}\) | |
| \(\frac{5}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (4 + 2) ÷ 5 x 2 - 42
P: 3 + (6) ÷ 5 x 2 - 42
E: 3 + 6 ÷ 5 x 2 - 16
MD: 3 + \( \frac{6}{5} \) x 2 - 16
MD: 3 + \( \frac{12}{5} \) - 16
AS: \( \frac{15}{5} \) + \( \frac{12}{5} \) - 16
AS: \( \frac{27}{5} \) - 16
AS: \( \frac{27 - 80}{5} \)
\( \frac{-53}{5} \)
-10\(\frac{3}{5}\)
How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?
| 4 | |
| 8 | |
| 4 | |
| 9 |
To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4