| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.58 |
| Score | 0% | 72% |
What is \( \sqrt{\frac{36}{49}} \)?
| \(\frac{2}{9}\) | |
| 1\(\frac{1}{3}\) | |
| \(\frac{6}{7}\) | |
| \(\frac{2}{3}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{36}{49}} \)
\( \frac{\sqrt{36}}{\sqrt{49}} \)
\( \frac{\sqrt{6^2}}{\sqrt{7^2}} \)
\(\frac{6}{7}\)
Find the average of the following numbers: 9, 7, 12, 4.
| 8 | |
| 12 | |
| 9 | |
| 7 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{9 + 7 + 12 + 4}{4} \) = \( \frac{32}{4} \) = 8
What is 5z3 x 3z4?
| 8z12 | |
| 15z-1 | |
| 15z7 | |
| 8z7 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
5z3 x 3z4
(5 x 3)z(3 + 4)
15z7
Charlie loaned Latoya $1,300 at an annual interest rate of 7%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,339 | |
| $1,365 | |
| $1,326 | |
| $1,391 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,300
i = 0.07 x $1,300
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,300 + $91What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 23 | |
| 31 | |
| 22 | |
| 34 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31