ASVAB Arithmetic Reasoning Practice Test 745331 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

What is \( \sqrt{\frac{25}{81}} \)?

70% Answer Correctly
\(\frac{2}{9}\)
\(\frac{5}{9}\)
\(\frac{6}{7}\)
\(\frac{1}{2}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{25}{81}} \)
\( \frac{\sqrt{25}}{\sqrt{81}} \)
\( \frac{\sqrt{5^2}}{\sqrt{9^2}} \)
\(\frac{5}{9}\)


2

A triathlon course includes a 300m swim, a 50.3km bike ride, and a 8.9km run. What is the total length of the race course?

69% Answer Correctly
29.2km
57.5km
66.1km
59.5km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.3km + 50.3km + 8.9km
total distance = 59.5km


3

What is 6c6 + 9c6?

66% Answer Correctly
15c6
15c-12
-3c6
3c6

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

6c6 + 9c6
(6 + 9)c6
15c6


4

What is -4x2 - 7x2?

71% Answer Correctly
11x2
3x4
-11x-2
-11x2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-4x2 - 7x2
(-4 - 7)x2
-11x2


5

What is \( 7 \)\( \sqrt{32} \) - \( 4 \)\( \sqrt{2} \)

38% Answer Correctly
3\( \sqrt{-12} \)
3\( \sqrt{2} \)
28\( \sqrt{16} \)
24\( \sqrt{2} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{32} \) - 4\( \sqrt{2} \)
7\( \sqrt{16 \times 2} \) - 4\( \sqrt{2} \)
7\( \sqrt{4^2 \times 2} \) - 4\( \sqrt{2} \)
(7)(4)\( \sqrt{2} \) - 4\( \sqrt{2} \)
28\( \sqrt{2} \) - 4\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

28\( \sqrt{2} \) - 4\( \sqrt{2} \)
(28 - 4)\( \sqrt{2} \)
24\( \sqrt{2} \)