| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
What is \( \frac{7}{6} \) + \( \frac{3}{12} \)?
| 1\(\frac{5}{12}\) | |
| 2 \( \frac{9}{13} \) | |
| \( \frac{6}{11} \) | |
| 1 \( \frac{1}{12} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 6 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 2}{6 x 2} \) + \( \frac{3 x 1}{12 x 1} \)
\( \frac{14}{12} \) + \( \frac{3}{12} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{14 + 3}{12} \) = \( \frac{17}{12} \) = 1\(\frac{5}{12}\)
The total water usage for a city is 25,000 gallons each day. Of that total, 16% is for personal use and 47% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 14,400 | |
| 7,750 | |
| 3,300 | |
| 2,400 |
47% of the water consumption is industrial use and 16% is personal use so (47% - 16%) = 31% more water is used for industrial purposes. 25,000 gallons are consumed daily so industry consumes \( \frac{31}{100} \) x 25,000 gallons = 7,750 gallons.
What is \( \frac{-7y^5}{3y^2} \)?
| -2\(\frac{1}{3}\)y7 | |
| -2\(\frac{1}{3}\)y10 | |
| -2\(\frac{1}{3}\)y3 | |
| -2\(\frac{1}{3}\)y-3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-7y^5}{3y^2} \)
\( \frac{-7}{3} \) y(5 - 2)
-2\(\frac{1}{3}\)y3
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 31 | |
| 36 | |
| 30 | |
| 35 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
A triathlon course includes a 500m swim, a 50.8km bike ride, and a 5.1km run. What is the total length of the race course?
| 42km | |
| 47.6km | |
| 40.8km | |
| 56.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.5km + 50.8km + 5.1km
total distance = 56.4km