| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
Monty loaned Bob $1,100 at an annual interest rate of 3%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $15 | |
| $54 | |
| $24 | |
| $33 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,100
i = 0.03 x $1,100
i = $33
If there were a total of 350 raffle tickets sold and you bought 7 tickets, what's the probability that you'll win the raffle?
| 15% | |
| 2% | |
| 18% | |
| 14% |
You have 7 out of the total of 350 raffle tickets sold so you have a (\( \frac{7}{350} \)) x 100 = \( \frac{7 \times 100}{350} \) = \( \frac{700}{350} \) = 2% chance to win the raffle.
What is \( \frac{9}{3} \) - \( \frac{5}{5} \)?
| 2 | |
| \( \frac{4}{10} \) | |
| \( \frac{1}{6} \) | |
| 2 \( \frac{9}{15} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 5}{3 x 5} \) - \( \frac{5 x 3}{5 x 3} \)
\( \frac{45}{15} \) - \( \frac{15}{15} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{45 - 15}{15} \) = \( \frac{30}{15} \) = 2
Convert c-2 to remove the negative exponent.
| \( \frac{2}{c} \) | |
| \( \frac{-1}{-2c^{2}} \) | |
| \( \frac{1}{c^2} \) | |
| \( \frac{1}{c^{-2}} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
A machine in a factory has an error rate of 4 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 98.9 | |
| 103 | |
| 154.7 | |
| 105.6 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{4}{100} \) x 5 = \( \frac{4 \times 5}{100} \) = \( \frac{20}{100} \) = 0.2 errors per hour
So, in an average hour, the machine will produce 5 - 0.2 = 4.8 error free parts.
The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 4.8 = 105.6 error free parts were produced yesterday.