If the tiger has consumed 105 pounds of food in 7 days that's \( \frac{105}{7} \) = 15 pounds of food per day. The tiger needs to consume 165 - 105 = 60 more pounds of food to reach 165 pounds total. At 15 pounds of food per day that's \( \frac{60}{15} \) = 4 more days.

49% of the water consumption is industrial use and 31% is personal use so (49% - 31%) = 18% more water is used for industrial purposes. 35,000 gallons are consumed daily so industry consumes \( \frac{18}{100} \) x 35,000 gallons = 6,300 gallons.

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{4}} \)
\( \frac{\sqrt{49}}{\sqrt{4}} \)
\( \frac{\sqrt{7^2}}{\sqrt{2^2}} \)
\( \frac{7}{2} \)
3\(\frac{1}{2}\)

To subtract these radicals together their radicands must be the same:

2\( \sqrt{28} \) - 9\( \sqrt{7} \)
2\( \sqrt{4 \times 7} \) - 9\( \sqrt{7} \)
2\( \sqrt{2^2 \times 7} \) - 9\( \sqrt{7} \)
(2)(2)\( \sqrt{7} \) - 9\( \sqrt{7} \)
4\( \sqrt{7} \) - 9\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.

Putting these two equations together and solving for width (w):

2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9

Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m²