To find the average of these 4 numbers add them together then divide by 4:

\( \frac{16 + 8 + 13 + 11}{4} \) = \( \frac{48}{4} \) = 12

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (2 + 3) ÷ 3 x 2 - 3²
P: 3 + (5) ÷ 3 x 2 - 3²
E: 3 + 5 ÷ 3 x 2 - 9
MD: 3 + \( \frac{5}{3} \) x 2 - 9
MD: 3 + \( \frac{10}{3} \) - 9
AS: \( \frac{9}{3} \) + \( \frac{10}{3} \) - 9
AS: \( \frac{19}{3} \) - 9
AS: \( \frac{19 - 27}{3} \)
\( \frac{-8}{3} \)
-2\(\frac{2}{3}\)

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 14 are [14, 28, 42, 56, 70, 84, 98]. The first few multiples they share are [42, 84] making 42 the smallest multiple 6 and 14 have in common.

The amount of flour you need is (2\(\frac{3}{4}\) - 1\(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{22}{8} \) - \( \frac{12}{8} \)) cups
\( \frac{10}{8} \) cups
1\(\frac{1}{4}\) cups