| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
If there were a total of 350 raffle tickets sold and you bought 31 tickets, what's the probability that you'll win the raffle?
| 10% | |
| 17% | |
| 9% | |
| 5% |
You have 31 out of the total of 350 raffle tickets sold so you have a (\( \frac{31}{350} \)) x 100 = \( \frac{31 \times 100}{350} \) = \( \frac{3100}{350} \) = 9% chance to win the raffle.
Solve for \( \frac{6!}{3!} \)
| 120 | |
| \( \frac{1}{56} \) | |
| 1680 | |
| \( \frac{1}{5} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{6!}{3!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{6 \times 5 \times 4}{1} \)
\( 6 \times 5 \times 4 \)
120
Christine scored 84% on her final exam. If each question was worth 3 points and there were 210 possible points on the exam, how many questions did Christine answer correctly?
| 55 | |
| 68 | |
| 59 | |
| 51 |
Christine scored 84% on the test meaning she earned 84% of the possible points on the test. There were 210 possible points on the test so she earned 210 x 0.84 = 177 points. Each question is worth 3 points so she got \( \frac{177}{3} \) = 59 questions right.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Alex buys two shirts, each with a regular price of $46, how much money will he save?
| $2.30 | |
| $20.70 | |
| $16.10 | |
| $13.80 |
By buying two shirts, Alex will save $46 x \( \frac{30}{100} \) = \( \frac{$46 x 30}{100} \) = \( \frac{$1380}{100} \) = $13.80 on the second shirt.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
|
distributive property for division |
|
commutative property for division |
|
distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).