| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
Solve for \( \frac{2!}{5!} \)
| 6 | |
| \( \frac{1}{60} \) | |
| \( \frac{1}{1680} \) | |
| 120 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{5!} \)
\( \frac{2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4 \times 3} \)
\( \frac{1}{60} \)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Ezra buys two shirts, each with a regular price of $50, how much money will he save?
| $12.50 | |
| $15.00 | |
| $25.00 | |
| $2.50 |
By buying two shirts, Ezra will save $50 x \( \frac{50}{100} \) = \( \frac{$50 x 50}{100} \) = \( \frac{$2500}{100} \) = $25.00 on the second shirt.
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 49:2 | |
| 7:2 | |
| 9:1 | |
| 7:8 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
What is 2c7 - 5c7?
| -3c7 | |
| 7c49 | |
| 7c7 | |
| 3c7 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
2c7 - 5c7
(2 - 5)c7
-3c7
Christine scored 91% on her final exam. If each question was worth 4 points and there were 400 possible points on the exam, how many questions did Christine answer correctly?
| 97 | |
| 79 | |
| 90 | |
| 91 |
Christine scored 91% on the test meaning she earned 91% of the possible points on the test. There were 400 possible points on the test so she earned 400 x 0.91 = 364 points. Each question is worth 4 points so she got \( \frac{364}{4} \) = 91 questions right.