| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
How many 9-passenger vans will it take to drive all 34 members of the football team to an away game?
| 4 vans | |
| 8 vans | |
| 12 vans | |
| 5 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{34}{9} \) = 3\(\frac{7}{9}\)
So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.
Simplify \( \frac{40}{72} \).
| \( \frac{4}{9} \) | |
| \( \frac{5}{18} \) | |
| \( \frac{6}{19} \) | |
| \( \frac{5}{9} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{40}{72} \) = \( \frac{\frac{40}{8}}{\frac{72}{8}} \) = \( \frac{5}{9} \)
A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have \(\frac{3}{8}\) cup, how much more flour is needed?
| 2 cups | |
| \(\frac{1}{2}\) cups | |
| 2\(\frac{5}{8}\) cups | |
| 2\(\frac{7}{8}\) cups |
The amount of flour you need is (3\(\frac{1}{4}\) - \(\frac{3}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{26}{8} \) - \( \frac{3}{8} \)) cups
\( \frac{23}{8} \) cups
2\(\frac{7}{8}\) cups
What is \( \frac{2}{4} \) - \( \frac{8}{10} \)?
| 1 \( \frac{3}{20} \) | |
| 2 \( \frac{4}{20} \) | |
| 1 \( \frac{2}{20} \) | |
| -\(\frac{3}{10}\) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [20, 40, 60, 80] making 20 the smallest multiple 4 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 5}{4 x 5} \) - \( \frac{8 x 2}{10 x 2} \)
\( \frac{10}{20} \) - \( \frac{16}{20} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{10 - 16}{20} \) = \( \frac{-6}{20} \) = -\(\frac{3}{10}\)
What is \( \frac{16\sqrt{35}}{8\sqrt{5}} \)?
| 7 \( \sqrt{2} \) | |
| 2 \( \sqrt{7} \) | |
| 2 \( \sqrt{\frac{1}{7}} \) | |
| \(\frac{1}{2}\) \( \sqrt{\frac{1}{7}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{16\sqrt{35}}{8\sqrt{5}} \)
\( \frac{16}{8} \) \( \sqrt{\frac{35}{5}} \)
2 \( \sqrt{7} \)