| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
What is \( 4 \)\( \sqrt{175} \) - \( 3 \)\( \sqrt{7} \)
| 17\( \sqrt{7} \) | |
| 12\( \sqrt{25} \) | |
| \( \sqrt{25} \) | |
| 12\( \sqrt{175} \) |
To subtract these radicals together their radicands must be the same:
4\( \sqrt{175} \) - 3\( \sqrt{7} \)
4\( \sqrt{25 \times 7} \) - 3\( \sqrt{7} \)
4\( \sqrt{5^2 \times 7} \) - 3\( \sqrt{7} \)
(4)(5)\( \sqrt{7} \) - 3\( \sqrt{7} \)
20\( \sqrt{7} \) - 3\( \sqrt{7} \)
Now that the radicands are identical, you can subtract them:
20\( \sqrt{7} \) - 3\( \sqrt{7} \)If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 9 | |
| 13 | |
| 14 | |
| 19 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 6 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 6 x 3 = 18 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 18 - 9 = 9 new staff for the busy season.
Convert a-2 to remove the negative exponent.
| \( \frac{1}{a^{-2}} \) | |
| \( \frac{-1}{a^{-2}} \) | |
| \( \frac{-1}{-2a^{2}} \) | |
| \( \frac{1}{a^2} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Solve 5 + (5 + 4) ÷ 3 x 2 - 52
| 1\(\frac{1}{2}\) | |
| 1 | |
| -14 | |
| \(\frac{5}{6}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (5 + 4) ÷ 3 x 2 - 52
P: 5 + (9) ÷ 3 x 2 - 52
E: 5 + 9 ÷ 3 x 2 - 25
MD: 5 + \( \frac{9}{3} \) x 2 - 25
MD: 5 + \( \frac{18}{3} \) - 25
AS: \( \frac{15}{3} \) + \( \frac{18}{3} \) - 25
AS: \( \frac{33}{3} \) - 25
AS: \( \frac{33 - 75}{3} \)
\( \frac{-42}{3} \)
-14
What is \( \frac{2}{5} \) x \( \frac{2}{5} \)?
| \(\frac{4}{25}\) | |
| \(\frac{4}{35}\) | |
| \(\frac{4}{5}\) | |
| \(\frac{3}{16}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{5} \) x \( \frac{2}{5} \) = \( \frac{2 x 2}{5 x 5} \) = \( \frac{4}{25} \) = \(\frac{4}{25}\)