ASVAB Arithmetic Reasoning Practice Test 761582 Results

Your Results Global Average
Questions 5 5
Correct 0 2.86
Score 0% 57%

Review

1

What is \( 4 \)\( \sqrt{175} \) - \( 3 \)\( \sqrt{7} \)

38% Answer Correctly
17\( \sqrt{7} \)
12\( \sqrt{25} \)
\( \sqrt{25} \)
12\( \sqrt{175} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{175} \) - 3\( \sqrt{7} \)
4\( \sqrt{25 \times 7} \) - 3\( \sqrt{7} \)
4\( \sqrt{5^2 \times 7} \) - 3\( \sqrt{7} \)
(4)(5)\( \sqrt{7} \) - 3\( \sqrt{7} \)
20\( \sqrt{7} \) - 3\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

20\( \sqrt{7} \) - 3\( \sqrt{7} \)
(20 - 3)\( \sqrt{7} \)
17\( \sqrt{7} \)


2

If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?

55% Answer Correctly
9
13
14
19

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 6 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 6 x 3 = 18 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 18 - 9 = 9 new staff for the busy season.


3

Convert a-2 to remove the negative exponent.

67% Answer Correctly
\( \frac{1}{a^{-2}} \)
\( \frac{-1}{a^{-2}} \)
\( \frac{-1}{-2a^{2}} \)
\( \frac{1}{a^2} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


4

Solve 5 + (5 + 4) ÷ 3 x 2 - 52

52% Answer Correctly
1\(\frac{1}{2}\)
1
-14
\(\frac{5}{6}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

5 + (5 + 4) ÷ 3 x 2 - 52
P: 5 + (9) ÷ 3 x 2 - 52
E: 5 + 9 ÷ 3 x 2 - 25
MD: 5 + \( \frac{9}{3} \) x 2 - 25
MD: 5 + \( \frac{18}{3} \) - 25
AS: \( \frac{15}{3} \) + \( \frac{18}{3} \) - 25
AS: \( \frac{33}{3} \) - 25
AS: \( \frac{33 - 75}{3} \)
\( \frac{-42}{3} \)
-14


5

What is \( \frac{2}{5} \) x \( \frac{2}{5} \)?

72% Answer Correctly
\(\frac{4}{25}\)
\(\frac{4}{35}\)
\(\frac{4}{5}\)
\(\frac{3}{16}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{5} \) x \( \frac{2}{5} \) = \( \frac{2 x 2}{5 x 5} \) = \( \frac{4}{25} \) = \(\frac{4}{25}\)