| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.89 |
| Score | 0% | 58% |
What is the greatest common factor of 20 and 48?
| 4 | |
| 11 | |
| 16 | |
| 3 |
The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 3 factors [1, 2, 4] making 4 the greatest factor 20 and 48 have in common.
| 1 | |
| 3.6 | |
| 3.2 | |
| 1.2 |
1
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 9 to 2 and the ratio of baseball to basketball cards is 9 to 1, what is the ratio of football to basketball cards?
| 9:8 | |
| 3:1 | |
| 81:2 | |
| 3:2 |
The ratio of football cards to baseball cards is 9:2 and the ratio of baseball cards to basketball cards is 9:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 81:18 and the ratio of baseball cards to basketball cards as 18:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 81:18, 18:2 which reduces to 81:2.
If a rectangle is twice as long as it is wide and has a perimeter of 18 meters, what is the area of the rectangle?
| 162 m2 | |
| 128 m2 | |
| 18 m2 | |
| 98 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 18 meters so the equation becomes: 2w + 2h = 18.
Putting these two equations together and solving for width (w):
2w + 2h = 18
w + h = \( \frac{18}{2} \)
w + h = 9
w = 9 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 9 - 2w
3w = 9
w = \( \frac{9}{3} \)
w = 3
Since h = 2w that makes h = (2 x 3) = 6 and the area = h x w = 3 x 6 = 18 m2
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Charlie buys two shirts, each with a regular price of $43, how much will he pay for both shirts?
| $77.40 | |
| $34.40 | |
| $62.35 | |
| $8.60 |
By buying two shirts, Charlie will save $43 x \( \frac{20}{100} \) = \( \frac{$43 x 20}{100} \) = \( \frac{$860}{100} \) = $8.60 on the second shirt.
So, his total cost will be
$43.00 + ($43.00 - $8.60)
$43.00 + $34.40
$77.40