A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (5 + 5) ÷ 4 x 3 - 4²
P: 4 + (10) ÷ 4 x 3 - 4²
E: 4 + 10 ÷ 4 x 3 - 16
MD: 4 + \( \frac{10}{4} \) x 3 - 16
MD: 4 + \( \frac{30}{4} \) - 16
AS: \( \frac{16}{4} \) + \( \frac{30}{4} \) - 16
AS: \( \frac{46}{4} \) - 16
AS: \( \frac{46 - 64}{4} \)
\( \frac{-18}{4} \)
-4\(\frac{1}{2}\)

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

8x⁶ + 8x⁶
(8 + 8)x⁶
16x⁶

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{92}{9} \) = 10\(\frac{2}{9}\)

So, it will take 10 full vans and one partially full van to transport the entire team making a total of 11 vans.