| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
Which of these numbers is a factor of 64?
| 1 | |
| 55 | |
| 7 | |
| 25 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 64 are 1, 2, 4, 8, 16, 32, 64.
Monica scored 90% on her final exam. If each question was worth 2 points and there were 100 possible points on the exam, how many questions did Monica answer correctly?
| 45 | |
| 36 | |
| 48 | |
| 60 |
Monica scored 90% on the test meaning she earned 90% of the possible points on the test. There were 100 possible points on the test so she earned 100 x 0.9 = 90 points. Each question is worth 2 points so she got \( \frac{90}{2} \) = 45 questions right.
What is \( \sqrt{\frac{4}{16}} \)?
| \(\frac{3}{4}\) | |
| 1 | |
| \(\frac{1}{2}\) | |
| 1\(\frac{1}{2}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{4}{16}} \)
\( \frac{\sqrt{4}}{\sqrt{16}} \)
\( \frac{\sqrt{2^2}}{\sqrt{4^2}} \)
\(\frac{1}{2}\)
Simplify \( \sqrt{63} \)
| 6\( \sqrt{14} \) | |
| 5\( \sqrt{7} \) | |
| 9\( \sqrt{14} \) | |
| 3\( \sqrt{7} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{63} \)
\( \sqrt{9 \times 7} \)
\( \sqrt{3^2 \times 7} \)
3\( \sqrt{7} \)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
|
distributive property for multiplication |
|
commutative property for division |
|
distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).