ASVAB Arithmetic Reasoning Practice Test 766396 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

Which of these numbers is a factor of 64?

69% Answer Correctly
1
55
7
25

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 64 are 1, 2, 4, 8, 16, 32, 64.


2

Monica scored 90% on her final exam. If each question was worth 2 points and there were 100 possible points on the exam, how many questions did Monica answer correctly?

57% Answer Correctly
45
36
48
60

Solution

Monica scored 90% on the test meaning she earned 90% of the possible points on the test. There were 100 possible points on the test so she earned 100 x 0.9 = 90 points. Each question is worth 2 points so she got \( \frac{90}{2} \) = 45 questions right.


3

What is \( \sqrt{\frac{4}{16}} \)?

70% Answer Correctly
\(\frac{3}{4}\)
1
\(\frac{1}{2}\)
1\(\frac{1}{2}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{4}{16}} \)
\( \frac{\sqrt{4}}{\sqrt{16}} \)
\( \frac{\sqrt{2^2}}{\sqrt{4^2}} \)
\(\frac{1}{2}\)


4

Simplify \( \sqrt{63} \)

62% Answer Correctly
6\( \sqrt{14} \)
5\( \sqrt{7} \)
9\( \sqrt{14} \)
3\( \sqrt{7} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{63} \)
\( \sqrt{9 \times 7} \)
\( \sqrt{3^2 \times 7} \)
3\( \sqrt{7} \)


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for multiplication

distributive property for multiplication

commutative property for division

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).