ASVAB Arithmetic Reasoning Practice Test 767973 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

What is \( \frac{4}{9} \) ÷ \( \frac{1}{8} \)?

68% Answer Correctly
3\(\frac{5}{9}\)
\(\frac{8}{45}\)
\(\frac{1}{18}\)
\(\frac{1}{21}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{9} \) ÷ \( \frac{1}{8} \) = \( \frac{4}{9} \) x \( \frac{8}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{8}{1} \) = \( \frac{4 x 8}{9 x 1} \) = \( \frac{32}{9} \) = 3\(\frac{5}{9}\)


2

What is 3\( \sqrt{4} \) x 2\( \sqrt{2} \)?

41% Answer Correctly
5\( \sqrt{8} \)
12\( \sqrt{2} \)
6\( \sqrt{6} \)
5\( \sqrt{2} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

3\( \sqrt{4} \) x 2\( \sqrt{2} \)
(3 x 2)\( \sqrt{4 \times 2} \)
6\( \sqrt{8} \)

Now we need to simplify the radical:

6\( \sqrt{8} \)
6\( \sqrt{2 \times 4} \)
6\( \sqrt{2 \times 2^2} \)
(6)(2)\( \sqrt{2} \)
12\( \sqrt{2} \)


3

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

greatest common factor

least common multiple

least common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


4

11 members of a bridal party need transported to a wedding reception but there are only 3 2-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
9
2
5
8

Solution

There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 11 people needing transportation leaving 11 - 6 = 5 who will have to find other transportation.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for multiplication

distributive property for division

commutative property for division

commutative property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).