| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
What is \( \frac{9}{8} \) + \( \frac{7}{12} \)?
| 1\(\frac{17}{24}\) | |
| \( \frac{7}{15} \) | |
| \( \frac{2}{6} \) | |
| 2 \( \frac{2}{24} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 3}{8 x 3} \) + \( \frac{7 x 2}{12 x 2} \)
\( \frac{27}{24} \) + \( \frac{14}{24} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{27 + 14}{24} \) = \( \frac{41}{24} \) = 1\(\frac{17}{24}\)
Bob loaned Damon $700 at an annual interest rate of 3%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $65 | |
| $21 | |
| $60 | |
| $8 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $700
i = 0.03 x $700
i = $21
What is 3\( \sqrt{9} \) x 9\( \sqrt{2} \)?
| 27\( \sqrt{11} \) | |
| 27\( \sqrt{2} \) | |
| 12\( \sqrt{2} \) | |
| 81\( \sqrt{2} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
3\( \sqrt{9} \) x 9\( \sqrt{2} \)
(3 x 9)\( \sqrt{9 \times 2} \)
27\( \sqrt{18} \)
Now we need to simplify the radical:
27\( \sqrt{18} \)
27\( \sqrt{2 \times 9} \)
27\( \sqrt{2 \times 3^2} \)
(27)(3)\( \sqrt{2} \)
81\( \sqrt{2} \)
What is the distance in miles of a trip that takes 6 hours at an average speed of 60 miles per hour?
| 240 miles | |
| 315 miles | |
| 360 miles | |
| 90 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 6h \)
360 miles
If \( \left|x - 5\right| \) + 5 = -9, which of these is a possible value for x?
| 0 | |
| -14 | |
| -9 | |
| 9 |
First, solve for \( \left|x - 5\right| \):
\( \left|x - 5\right| \) + 5 = -9
\( \left|x - 5\right| \) = -9 - 5
\( \left|x - 5\right| \) = -14
The value inside the absolute value brackets can be either positive or negative so (x - 5) must equal - 14 or --14 for \( \left|x - 5\right| \) to equal -14:
| x - 5 = -14 x = -14 + 5 x = -9 | x - 5 = 14 x = 14 + 5 x = 19 |
So, x = 19 or x = -9.