| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
Which of these numbers is a factor of 32?
| 33 | |
| 27 | |
| 1 | |
| 11 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 40,000 seats in a stadium are filled, how many home fans are in attendance?
| 25,500 | |
| 33,600 | |
| 30,000 | |
| 33,333 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
40,000 fans x \( \frac{5}{6} \) = \( \frac{200000}{6} \) = 33,333 fans.
What is \( \frac{2}{8} \) ÷ \( \frac{4}{7} \)?
| \(\frac{1}{14}\) | |
| \(\frac{1}{8}\) | |
| \(\frac{7}{16}\) | |
| 1\(\frac{3}{4}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{8} \) ÷ \( \frac{4}{7} \) = \( \frac{2}{8} \) x \( \frac{7}{4} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{8} \) x \( \frac{7}{4} \) = \( \frac{2 x 7}{8 x 4} \) = \( \frac{14}{32} \) = \(\frac{7}{16}\)
How many hours does it take a car to travel 30 miles at an average speed of 30 miles per hour?
| 5 hours | |
| 2 hours | |
| 9 hours | |
| 1 hour |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{30mi}{30mph} \)
1 hour
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
|
distributive property for multiplication |
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commutative property for division |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).