| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.60 |
| Score | 0% | 72% |
What is (b2)4?
| b8 | |
| b6 | |
| 2b4 | |
| b2 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b2)4If there were a total of 450 raffle tickets sold and you bought 27 tickets, what's the probability that you'll win the raffle?
| 6% | |
| 5% | |
| 17% | |
| 14% |
You have 27 out of the total of 450 raffle tickets sold so you have a (\( \frac{27}{450} \)) x 100 = \( \frac{27 \times 100}{450} \) = \( \frac{2700}{450} \) = 6% chance to win the raffle.
10 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 53 | |
| 4 | |
| 5 |
There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 10 people needing transportation leaving 10 - 9 = 1 who will have to find other transportation.
4! = ?
3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
|
4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is \( \frac{6}{3} \) - \( \frac{4}{7} \)?
| 1 \( \frac{2}{21} \) | |
| 1\(\frac{3}{7}\) | |
| 1 \( \frac{7}{21} \) | |
| \( \frac{5}{11} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{6 x 7}{3 x 7} \) - \( \frac{4 x 3}{7 x 3} \)
\( \frac{42}{21} \) - \( \frac{12}{21} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{42 - 12}{21} \) = \( \frac{30}{21} \) = 1\(\frac{3}{7}\)