ASVAB Arithmetic Reasoning Practice Test 771795 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

How many 7-passenger vans will it take to drive all 87 members of the football team to an away game?

81% Answer Correctly
13 vans
4 vans
6 vans
8 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{87}{7} \) = 12\(\frac{3}{7}\)

So, it will take 12 full vans and one partially full van to transport the entire team making a total of 13 vans.


2

What is \( 5 \)\( \sqrt{18} \) + \( 3 \)\( \sqrt{2} \)

35% Answer Correctly
15\( \sqrt{18} \)
18\( \sqrt{2} \)
15\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To add these radicals together their radicands must be the same:

5\( \sqrt{18} \) + 3\( \sqrt{2} \)
5\( \sqrt{9 \times 2} \) + 3\( \sqrt{2} \)
5\( \sqrt{3^2 \times 2} \) + 3\( \sqrt{2} \)
(5)(3)\( \sqrt{2} \) + 3\( \sqrt{2} \)
15\( \sqrt{2} \) + 3\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

15\( \sqrt{2} \) + 3\( \sqrt{2} \)
(15 + 3)\( \sqrt{2} \)
18\( \sqrt{2} \)


3

Diane scored 87% on her final exam. If each question was worth 4 points and there were 240 possible points on the exam, how many questions did Diane answer correctly?

57% Answer Correctly
38
52
39
66

Solution

Diane scored 87% on the test meaning she earned 87% of the possible points on the test. There were 240 possible points on the test so she earned 240 x 0.87 = 208 points. Each question is worth 4 points so she got \( \frac{208}{4} \) = 52 questions right.


4

What is \( \frac{2}{7} \) ÷ \( \frac{2}{8} \)?

68% Answer Correctly
\(\frac{4}{35}\)
\(\frac{8}{63}\)
1\(\frac{1}{7}\)
2\(\frac{2}{7}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{7} \) ÷ \( \frac{2}{8} \) = \( \frac{2}{7} \) x \( \frac{8}{2} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{7} \) x \( \frac{8}{2} \) = \( \frac{2 x 8}{7 x 2} \) = \( \frac{16}{14} \) = 1\(\frac{1}{7}\)


5

What is \( \frac{-8y^6}{9y^2} \)?

60% Answer Correctly
-1\(\frac{1}{8}\)y4
-1\(\frac{1}{8}\)y8
-\(\frac{8}{9}\)y4
-\(\frac{8}{9}\)y3

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-8y^6}{9y^2} \)
\( \frac{-8}{9} \) y(6 - 2)
-\(\frac{8}{9}\)y4