ASVAB Arithmetic Reasoning Practice Test 773751 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

Bob loaned Bob $800 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$117
$42
$40
$72

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $800
i = 0.09 x $800
i = $72


2

A triathlon course includes a 100m swim, a 30.3km bike ride, and a 8.8km run. What is the total length of the race course?

69% Answer Correctly
39.2km
49.7km
47km
33.3km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.1km + 30.3km + 8.8km
total distance = 39.2km


3

A machine in a factory has an error rate of 9 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 7 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
126.9
160.2
77.4
129.2

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{9}{100} \) x 5 = \( \frac{9 \times 5}{100} \) = \( \frac{45}{100} \) = 0.45 errors per hour

So, in an average hour, the machine will produce 5 - 0.45 = 4.55 error free parts.

The machine ran for 24 - 7 = 17 hours yesterday so you would expect that 17 x 4.55 = 77.4 error free parts were produced yesterday.


4

What is \( 7 \)\( \sqrt{48} \) - \( 4 \)\( \sqrt{3} \)

38% Answer Correctly
24\( \sqrt{3} \)
3\( \sqrt{-7} \)
28\( \sqrt{48} \)
3\( \sqrt{144} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{48} \) - 4\( \sqrt{3} \)
7\( \sqrt{16 \times 3} \) - 4\( \sqrt{3} \)
7\( \sqrt{4^2 \times 3} \) - 4\( \sqrt{3} \)
(7)(4)\( \sqrt{3} \) - 4\( \sqrt{3} \)
28\( \sqrt{3} \) - 4\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

28\( \sqrt{3} \) - 4\( \sqrt{3} \)
(28 - 4)\( \sqrt{3} \)
24\( \sqrt{3} \)


5

What is the least common multiple of 6 and 10?

72% Answer Correctly
51
19
2
30

Solution

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 have in common.