ASVAB Arithmetic Reasoning Practice Test 775997 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

53% Answer Correctly
3.2
0.9
1
1.0

Solution


1


2

Simplify \( \frac{24}{60} \).

77% Answer Correctly
\( \frac{2}{3} \)
\( \frac{10}{11} \)
\( \frac{10}{13} \)
\( \frac{2}{5} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 24 are [1, 2, 3, 4, 6, 8, 12, 24] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 3, 4, 6, 12] making 12 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{24}{60} \) = \( \frac{\frac{24}{12}}{\frac{60}{12}} \) = \( \frac{2}{5} \)


3

A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
17\(\frac{1}{2}\)%
15%
37\(\frac{1}{2}\)%
27\(\frac{1}{2}\)%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%


4

What is \( \frac{25\sqrt{8}}{5\sqrt{2}} \)?

71% Answer Correctly
4 \( \sqrt{5} \)
4 \( \sqrt{\frac{1}{5}} \)
5 \( \sqrt{4} \)
5 \( \sqrt{\frac{1}{4}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{25\sqrt{8}}{5\sqrt{2}} \)
\( \frac{25}{5} \) \( \sqrt{\frac{8}{2}} \)
5 \( \sqrt{4} \)


5

Which of the following is a mixed number?

82% Answer Correctly

\({a \over 5} \)

\(1 {2 \over 5} \)

\({5 \over 7} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.